2[m-(4m+12)+2]=2(m+10)

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Solution for 2[m-(4m+12)+2]=2(m+10) equation:


Simplifying
2[m + -1(4m + 12) + 2] = 2(m + 10)

Reorder the terms:
2[m + -1(12 + 4m) + 2] = 2(m + 10)
2[m + (12 * -1 + 4m * -1) + 2] = 2(m + 10)
2[m + (-12 + -4m) + 2] = 2(m + 10)

Reorder the terms:
2[-12 + 2 + m + -4m] = 2(m + 10)

Combine like terms: -12 + 2 = -10
2[-10 + m + -4m] = 2(m + 10)

Combine like terms: m + -4m = -3m
2[-10 + -3m] = 2(m + 10)
[-10 * 2 + -3m * 2] = 2(m + 10)
[-20 + -6m] = 2(m + 10)

Reorder the terms:
-20 + -6m = 2(10 + m)
-20 + -6m = (10 * 2 + m * 2)
-20 + -6m = (20 + 2m)

Solving
-20 + -6m = 20 + 2m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2m' to each side of the equation.
-20 + -6m + -2m = 20 + 2m + -2m

Combine like terms: -6m + -2m = -8m
-20 + -8m = 20 + 2m + -2m

Combine like terms: 2m + -2m = 0
-20 + -8m = 20 + 0
-20 + -8m = 20

Add '20' to each side of the equation.
-20 + 20 + -8m = 20 + 20

Combine like terms: -20 + 20 = 0
0 + -8m = 20 + 20
-8m = 20 + 20

Combine like terms: 20 + 20 = 40
-8m = 40

Divide each side by '-8'.
m = -5

Simplifying
m = -5

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